RT3: 0.40 pmol/mL (0.14-0.54)
FT3: 6 pmol/L (2.7-7)
How do I do the ration when its as above?
Thanks guys
RT3: 0.40 pmol/mL (0.14-0.54)
FT3: 6 pmol/L (2.7-7)
How do I do the ration when its as above?
Thanks guys
There you go
0.40 pmol/mL is 400 pmol/L
6 pmol/L is 0.006 pmol/mL
But that looks even less likely. Are you sure they are both in picomols (pmol)?
Bexy, The STTM book gives this advice:
1. If both RT3 and Free T3 are in pmol/L or pg/mL, multiply the free T3 by 1000, divide the Free T3 by the RT3.
2. If theRT3 is nmol/L and Free T3 is pmol/L, divide the Free T3 by the RT3.
3. If the RT3 is ng/dL and Free T3 is pg/dL, divide the Free T3 by the RT3.
4. If the RT3 is pg/mL and Free T3 is pg/dL, multiply the Free T3 by 100, then divide Free T3 by RT3.
Your rt3 is high..you don't need the ratio to see that.